Maximum Transmit Power with mMIMO

So you find the answer. :wink:
Now you have to find what is it with 35.2 dBm, max tx power…

Yes, where does it come from? :slight_smile:

According to Huawei, for FDD 8T8R and 32T32R cells, this parameter indicates the cell max power of each logical ant.
Now, find out how many logical antennas you have.
CRS ports are logical antenna ports.
So, I think you have 4.

Symbols with RS (typeB) you will have two REs with 9.8 dBm, two more with nothing (other antenna ports), and the remaining with 5.03 dBm (9.8-4.77), when you sum them all, you get 16.49 dBm per PRB. Multiply by 75 PRBs for your total BW, you will get the 35.24 dBm.

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What is RE0, RE1, Type B?

In one PRB I have 4 RS (type B), correct?

Red means RS (TypeB).

Pa (mW) = Rs * 10 ^ (Pa / 10) and Pb (mW) = Pa (mW) * Pb / Pa
Pa = 3.16 mW = 4.99 dBm
Pb = 9.5 mW = 9.8 dBm
Pb is RE that cointan RS

These are sector beam ports I think 0,1,2,3.
For user beam virtual ports there.
Tm8 having port 7,8 for user beam.
Tm7 having port 5.

@marcengo, why are you considering only the symbol 1?

In PRB I have 4 (RS) and 8 (TypeB), am I correct?
Why are you considering only RS and TypeB in symbol 1?

My case was 2T, yours is correct.
For 4T, symb1 also carries REs for CRS.

It’s correct.
For the power we use 1 symbol.

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Thanks @marcengo

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I need to consider the MAXIMUM transmitted in one symbol. In my case, 35.2dBm.

What advantage does SOMA gives instead of OFDMA?
Does SOMA outplays than NOMA in case of SIC?
As a learner I understood that SOMA used for uplink.
Is this already used in 5G NR?

total transmit power=Pmax=10log(number of TRX)
if total power=200 W=53.01dbm & Number of TRX =64 ====>Pmax=53.01-10
log(64) ≈35 dbm

if total power=160 W=52.01dbm & Number of TRX =32 ====>Pmax=53.01-10*log(32) ≈37 dbm