For 5G PT-RS in FR2, If we set frequency density Kref =2 and time density Lptrs = 1 the PT-RS will be transmitted or not?
To be clear, I need to make time density to be low since high density in the time domain produces a phase noise.
So, is it better to choose 2 or 4?
I think it should be transmitted, as 3GPP specifies time density to be {1,2,4} and frequency density to be {2,4}.
In that case 2 would be a better choice, as higher time density of PTRS would lead to more accurate phase noise estimation.
For frequency density as 2 and time density as 1, right?
Yes, I think so.
Phase noise is better compensated with high density in time rather than in freq domain.
So which shall I used? Lptrs = 1 and kef = 2?
You should use 1 means every symbol PTRS will be transmitted.
Yes no doubt that overhead will increase but gives better result in phase noise.
So Lptrs = 1 is better for time?
Yes, correct.
What about frequency?
Density.
Kptrs= 2 or 4?
I think 4 is better?
4 means every 4 RB it will be tramsmitted.
Yes, correct.
So if you want more PTRS then use 2.
Kptrs = 2 provides high density than 4.
But not much impact in freq domain.
Yes correct 2 means every 2nd RB so density is high.
But, I think 2 is better because use more PTRS in resource block to avoid phase noise.
So, 2 is better to choose?
I just want to try avoid the phase noise since I am just simulate the design system.
Yes, correct.
And Lptrs = 1.
Yes, correct.
Great, thanks a lot! 
When I compute the BER and Throughput, it will get a good performance?
