How to calculate RS power?

If i have 20 MHz bw, by 80 W power, what will be the exact RS on the field?

Vendor is Ericsson.

Generally rs power = pmax - 10 log 10 (number of rb * 12 ) + any mimo gain.

Please use above formula and check in sib2 if value matches or not for rs power you calculated.

Pmax in dBm in above formula.

Find EPRE in type-A symbol and then use Pa, Pb values to find RS Power.

20 MHz BW, this implies 100 RB X 12 RE -> 1,200 RE

Total power = 8 W = 80,000 mWatt

Power per RE = 80,000 /1,200 = 66.66 mWatt

Let’s say Pa = -3, this implies Reference Signal is 3 dB stronger

(In Ericsson it’s equivalent to CRsgain = 300)

3 dB means double

So RS power will be 66.66 x 2 = 133.32 mili Watt

Convert it into dbm

10 log (133.32 mW / 1 mW) = 21.24 dBm

Assuming Pb = 1

Otherwise there will be power imbalance [either over or under Utilization]

Another assumption is 2x2 MIMO enabled.

Hope you got it :)… Cheers

Appreciated.

And how about if it have crsgain = 0?

It means RS power will be same as of EPRE.

So we calculated EPRE = 66.66 mWatt

In this case RS Power will be same i.e. 66.66 mWatt

Convert it into dBm.

10 log (66.66 mW / 1mW)

RS Pwr = 18.2386 dBm