How path loss is calculated by UE?

RAN
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1

Hi All,
Can anyone explain me in simple words how path loss is calculated by UE?
My understanding it’s as per measured RSRP.

I’m seeing there is no standard equation.

2

RS Power of eNB - RSRP at UE = Path loss

3

Sib1 broadcast eNB TX power?

4

Sib2 Rs power.

5

You can check below link, it quite detailed:

6

Hi Experts.

I read somewhere that maximum Pathloss is 152 dBm. But why it is 152dBm?

Is there any mathematical calculation for max Path Loss?

7

Of course there is link budget calculation with many elements like antenna gain etc.

8

And also Rx sensitivity.

And check this, quite detailed indeed:

9

Pathloss is expressed as dB not dBm. As gain or loss is ratio of output and input powers.

  • A = 10log( Pout/ Pin) log is taken to the base 10
  • A = power gain/loss in dB
  • Pout = output power level in watts
  • Pin = input power level in watts

Whereas signal strength is expressed in dBm as the reference power is taken as 1mw.

If the signal power level is 500me then in dBm it will be expressed as 10 log ( 50010^-3/110^-3) = 27 dBm

Path loss L= 20log(4*π/c) + 20log f + 20log D

  • c = velocity of light (3 * 10^8 m/s)
  • f = frequency in Hertz
  • D= Distance in km

If f is in MHz and D in km then path loss L = 32.4 + 20log f + 20log D
If f is in GHz and D is in km then path loss L = 92.4+20log f + 20log D