Hello Experts,
During LTE cell search procedure , how much time does UE take to complete PSS and SSS scan procedure ?
Like
t1 → PSS and SSS scan start
t2 → PSS and SSS scan start completed and derived cell id
is there any mathematical way i can represent
So i need time t1 to t2
In order to successfully detect the cell ID, UE has to
extract SID and GID from both the synchronization channels. There are 504 distinct cell IDs available in LTE,which are grouped into 168 distinct groups identified byGID. All the groups contain three identical SIDs. GID ∈ {0, 1, 2…,167} is carried by SSS, and SID ∈ {0, 1, 2} is carried by PSS.
Two OFDM symbols for each of PSCH and SSCH are transmitted in every frame with a separation of 5 ms. PSS present in the two symbols convey the same message, i.e.,SID. To differentiate the first and second half of a frame, SSS present in two symbols are not identical; however, they convey same information. The goal of the synchronization procedure is to align to the frame boundaries of
corresponding BS. The cell search and synchronization process will be complete if the UE performs the following operations successfully.
Ideal Conditions (Strong Signal and No Frequency Scanning):
PSS detection: ~1 ms
SSS detection: ~1 ms
Total time: ~2 ms
Frequency scanning depends on the number of candidate frequencies or bandwidths. For example:
If scanning 5 candidate frequencies, total time could increase to 5 × 2 ms = 10 ms, plus any overhead.
Typical total time: ~5–20 ms, depending on UE implementation and conditions.
This range (2–20 ms) aligns with LTE system expectations under 3GPP standards for initial cell search and synchronization….
Hello Ali_Khalaf
Thanks for explanation
“This range (2–20 ms) aligns with LTE system expectations under 3GPP standards for initial cell search and synchronization” → is there any spec and section statement i need to refer for this ?..i need as a reference
