I think i12 cannot be 10, maximum can be from 0 to 7 since N2 * O2 = 8.
For your first inquiry i11=7, i12=6, I think it will be like this: 
I am referring table 5.2.2.2.1-4 to map i13 to k1 and k2 for RI: 3 and no of csi rs port=8.
In my case i13 = 1 so k1 = 0 and k2 = O2.
From here i11 = 7+k1= 7
i12 = 6 + k2 = 6 + 4 = 10.
Correct me here.
I am just saying that I12 goes from 0 till N2 * O2 - 1.
But from the above table for second beam i12 is 10 as k2 = O2 = 4.
Yes agree with your point, but only I am thinking why in second beam position I am getting i12 = 10.
To calculate second beam position I used below expression.
i11 + k1 & i12 + k2 and then referred above table 5.2.2.2.1-4
Please correct me.
Are you referring to a hypothetical possible case or a real case?
It’s a real case.
First of all for RI =3, you need 2 beams (No of Beams = Ceiling [RI / 2])
N1 = 2, So, O1 = 4
N2 = 2, So O2 = 4
i11 = 0 to 7
i12= 0 to 7
So for the first beam, i11 = 7 and i12 = 6… as mentioned by @RFSpecialist
The 2nd beam is indicated by i13 and it represents the offset between the beams selected for each layer.
i13 = 0, 1, 2, 3.
For eg if i13 = 1, k1 = O1 = 4, k2 = 0, So
Let me correct you for my case with csi rs port : 8 and RI: 3,
K1 = 0 and K2 = O2 = 4.
Already I have covered all these points to get second beam position.
Refer this table, N1= N2= 2, i13= 1
K1 and K2 are only applicable for i13 i.e. for the 2nd beam.
It has nothing to do with i11 and i12.
Yes, and I am trying to find 2nd beam position with the help of this table. i13: 1.
This is the position of 2nd beam (Green colour) 
Just refer correct k1 and k2 for the case N1 / N2 = 1 and i13 = 1.
No of CSI rs port = 8.
But in your picture N1 = N2 = 2 why do you say now it is 1?
For i13 = 1 with N1 = N2 = 2, we are getting k1 = 0 and k2 = O2 = 4 from 3GPP table.
For i13 = 1👆
This one was for i13 = 0
Once you locate the 1st beam, it is simple to locate the 2nd one.
For 2nd beam, for i12 = 10…
Here index started from 8, 9 and then 10?
For 2nd beam, only i13 is applicable.
It is just an offset to the first beam (Here Offset Is 4 in vertical plane).
Okay! Now got it.
Thanks:+1:t2: